document.write( "Question 963081: I built a swimming pool that has an area of 540 square yards. The length is 1 2/3 times the amount of the width. What could be the dimensions of the pool? \n" ); document.write( "
Algebra.Com's Answer #602935 by justlikemath(2)\"\" \"About 
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given: area=540sq.yd ; \"+L=%281+%26+2%2F3%29%2Aw+\"\r
\n" ); document.write( "\n" ); document.write( "\"+A=L%2AW+\"\r
\n" ); document.write( "\n" ); document.write( "substitute values
\n" ); document.write( "\"+540=%281+%26+2%2F3%29%2Aw%2Aw+\"
\n" ); document.write( "\"+540=%281+%26+2%2F3%29w%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "i changed the mixed fraction to improper so that it would be easy to multiply and divide
\n" ); document.write( "\"+540=%285%2F3%29w%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "multiply both sides by 3 so that 3 in the denominator would be eliminated
\n" ); document.write( "\"+3%28540%29=%28%285%2F3%29w%5E2%293+\"
\n" ); document.write( "\"+1620=5w%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "divide both sides by 5 so that 5 would be eliminated and w^2 would remain
\n" ); document.write( "\"+1620%2F5=%285w%5E2%29%2F5+\"
\n" ); document.write( "\"+324=w%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "square both sides so that only w would remain
\n" ); document.write( "\"+sqrt%28324%29=sqrt%28w%5E2%29+\"
\n" ); document.write( "\"+18=w+\"\r
\n" ); document.write( "\n" ); document.write( "we already have the width=18
\n" ); document.write( "substitute to formula
\n" ); document.write( "\"+A=L%2AW+\"
\n" ); document.write( "\"+540=L%2A18+\"
\n" ); document.write( "\"+540=18L+\"
\n" ); document.write( "\"+540%2F18=%2818L%29%2F18+\"
\n" ); document.write( "\"+30=L+\"\r
\n" ); document.write( "\n" ); document.write( "therefore 30yards x 18yards is the dimension of the swimming pool
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