document.write( "Question 982028: solve using algebraic method. if possible check your solution
\n" ); document.write( "2x-5y=3
\n" ); document.write( "x-2y=7
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Algebra.Com's Answer #602901 by macston(5194)\"\" \"About 
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\n" ); document.write( "Second equation:
\n" ); document.write( "x-2y=7
\n" ); document.write( "x=2y+7
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\n" ); document.write( "First equation:
\n" ); document.write( "2x-5y=3 Substitute for x.
\n" ); document.write( "2(2y+7)-5y=3
\n" ); document.write( "4y+14-53y=3
\n" ); document.write( "-y+14=3
\n" ); document.write( "-y=-11
\n" ); document.write( "y=11
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\n" ); document.write( "x=2y+7
\n" ); document.write( "x=2(11)+7=29
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\n" ); document.write( "ANSWER: x=29 and y=11
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\n" ); document.write( "CHECK:
\n" ); document.write( "x-2y=7
\n" ); document.write( "29-2(11)=7
\n" ); document.write( "29-22=7
\n" ); document.write( "7=7
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\n" ); document.write( "CHECK 2:
\n" ); document.write( "2x-5y=3
\n" ); document.write( "2(29)-5(11)=3
\n" ); document.write( "58-55=3
\n" ); document.write( "3=3\r
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