document.write( "Question 982026: In a survey of 3238adults, 1442 say they have started paying bills online in the last year.
\n" ); document.write( "Construct a​ 99% confidence interval for the population proportion. Interpret the results.
\n" ); document.write( "A​ 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis(,).
\n" ); document.write( "​(Round to three decimal places as​ needed.)
\n" ); document.write( "A) The endpoints of the given confidence interval show that adults pay bills online​ 99% of the time.
\n" ); document.write( "B) With​ 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.
\n" ); document.write( "C) With​ 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.
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Algebra.Com's Answer #602889 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In a survey of 3238adults, 1442 say they have started paying bills online in the last year.
\n" ); document.write( "Construct a​ 99% confidence interval for the population proportion. Interpret the results.
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\n" ); document.write( "p-hat = 1442/3238 = 0.445
\n" ); document.write( "ME = 2.5758*sqrt[(1/2)(1/2)/3238) = 0.023
\n" ); document.write( "---
\n" ); document.write( "99%CI:: (0.445-0.023,0.445+0.023) = (0.422,0.468)
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\n" ); document.write( "\n" ); document.write( "A​ 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis(,).
\n" ); document.write( "​(Round to three decimal places as​ needed.)
\n" ); document.write( "A) The endpoints of the given confidence interval show that adults pay bills online​ 99% of the time. NO
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\n" ); document.write( "B) With​ 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval. NO
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\n" ); document.write( "C) With​ 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval. YES
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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