document.write( "Question 982011: Helen invested 40,000 and received a total of 2300.00 in interest after one year. If part of the money returned 5% and the remainder 8% then how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #602878 by macston(5194)\"\" \"About 
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\n" ); document.write( "F=amount invested at 5%; E=amount invested at 8%
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\n" ); document.write( "F+E=40000
\n" ); document.write( "E=40000-F Use this to substitute for E below.
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\n" ); document.write( "0.05F+0.08E=2300 Substitute for E.
\n" ); document.write( "0.05F+0.08(40000-F)=2300
\n" ); document.write( "0.05F+3200-0.08F=2300 Subtract 3200 from each side.
\n" ); document.write( "-0.03F=-900 Divide each side by -0.03.
\n" ); document.write( "F=30000 ANSWER 1: She invested 30000 at 5%.
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\n" ); document.write( "E=40000-F
\n" ); document.write( "E=40000-30000
\n" ); document.write( "E=10000 ANSWER 2: She invested 10000 at 8%.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.05F+0.08E=2300
\n" ); document.write( "0.05(30000)+0.08(10000)=2300
\n" ); document.write( "1500+800=23==
\n" ); document.write( "2300=2300\r
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