document.write( "Question 982009: An actress has to be on set, which is 21 miles away at 7am. If she wakes up at 5:30 am and does her make up for 48 minutes, how fast must she drive to get on to work on time? * step by step method please! THX! \n" ); document.write( "
Algebra.Com's Answer #602872 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Add 5:30 to 0:48 \r
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\n" ); document.write( "\n" ); document.write( "5:30
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\n" ); document.write( "6:18\r
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\n" ); document.write( "\n" ); document.write( "So she does her makeup, and when that is finished, she takes off at 6:18 am.\r
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\n" ); document.write( "\n" ); document.write( "The time difference from 6:18 am to 7:00 am is 42 minutes, which is 42/60 = 0.7 hrs\r
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\n" ); document.write( "\n" ); document.write( "She must drive 21 miles for 0.7 hours\r
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\n" ); document.write( "\n" ); document.write( "d = 21
\n" ); document.write( "r = unknown
\n" ); document.write( "t = 0.7\r
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\n" ); document.write( "\n" ); document.write( "Use the equation d = r*t to solve for r\r
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\n" ); document.write( "\n" ); document.write( "d = r*t\r
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\n" ); document.write( "\n" ); document.write( "21 = r*0.7\r
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\n" ); document.write( "\n" ); document.write( "21/0.7 = r*0.7/0.7 divide both sides by 0.7 to isolate r\r
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\n" ); document.write( "\n" ); document.write( "30 = r\r
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\n" ); document.write( "\n" ); document.write( "r = 30\r
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\n" ); document.write( "\n" ); document.write( "She must drive at least 30 mph to make it on time. I put \"at least\" in there to mean that if she drives faster than 30 mph, then she'll have a bit of time to spare.
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