document.write( "Question 981902: car A and car B start together. Car A travels once around the circular track at 30 mph. car b travels in the opposite direction at 20 mph, until he passes car A. From this point, at what speed must car B travel to finish once around the track at the same time that car A does? \n" ); document.write( "
Algebra.Com's Answer #602869 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! car A and car B start together. Car A travels once around the circular track at 30 mph. \n" ); document.write( " car b travels in the opposite direction at 20 mph, until he passes car A. \n" ); document.write( " From this point, at what speed must car B travel to finish once around the track at the same time that car A does? \n" ); document.write( ": \n" ); document.write( "Assume the distance around the track is 100 mi, not realistic, but convenient \n" ); document.write( "Let t = travel time for them to meet \n" ); document.write( "30t + 20t = 100 \n" ); document.write( "50t = 100 \n" ); document.write( "t = 100/50 \n" ); document.write( "t = 2 hrs for them to meet (sorry about this screw-up) \n" ); document.write( ": \n" ); document.write( "Find how far each traveled when they met \n" ); document.write( "2*30 = 60 mi by car A \n" ); document.write( "2*20 = 40 mi by car B \n" ); document.write( ": \n" ); document.write( "Find how long it will take Car A to travel the last 40 mi \n" ); document.write( "40/30 = 1.3333 hrs \n" ); document.write( ": \n" ); document.write( "Find how fast Car B has to go to cover his last 60 mi in 1.333 hrs \n" ); document.write( "60/1.333 = 45 mph for Car B to arrive at the starting point as the same time car A arrives \n" ); document.write( " |