document.write( "Question 981966: Please use the remainder theorem to evaluate \"4x%5E3+-+3x%5E2+%2B+2x+-+3+when+x=2\" \n" ); document.write( "
Algebra.Com's Answer #602843 by josgarithmetic(39620)\"\" \"About 
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This means, use synthetic division with \"root to check\" being 2 and dividend \"4x%5E3-3x%5E2%2B2x-3\". The remainder will be the given expression (your dividend) evaluated for x=2.\r
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\n" ); document.write( "\n" ); document.write( "Do you need to see the work?
\n" ); document.write( "response: YES.\r
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\n" ); document.write( "\n" ); document.write( "Root to check on the left, dividend coefficients on the other side of the \"vertical wall\". This shows a start setup of the synthetic division:\r
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\n" ); document.write( "______2____|_____4______-3______2_______-3
\n" ); document.write( "___________|
\n" ); document.write( "___________|_________________________________\r
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\n" ); document.write( "\n" ); document.write( "___________________________________________
\n" ); document.write( "___________|
\n" ); document.write( "______2____|_____4______-3______2_______-3
\n" ); document.write( "___________|____________8_______10______24
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\n" ); document.write( "_________________4_______5______12_______21\r
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\n" ); document.write( "\n" ); document.write( "The remainder is 21;
\n" ); document.write( "this means that 4x^3 - 3x^2 + 2x - 3 will be 21 for x=2.
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