document.write( "Question 981891: Ok so the problem is A rocket is launched from atop a 41 foot cliff with an initial velocity of 103 feet per second. The height of the rocket t seconds after launch is given by the equation . Graph the equation to find out how long after the rocket is launched it will hit the ground. Round to the nearest tenth of a second.
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document.write( "I know this is a large problem but please help and ill be very grateful.
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document.write( "I remember my math teacher asking this but it was 2 years ago so I forgot how to do it.
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document.write( " Please explain also. \n" );
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Algebra.Com's Answer #602807 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! The equation is \n" ); document.write( "h = -16t^2 +103t + 41 \n" ); document.write( "this is a parabola that opens downward \n" ); document.write( "to find time t when the rocket hits the round solve the following for t \n" ); document.write( "-16t^2 +103t + 41 = 0 \n" ); document.write( "use quadratic formula, \n" ); document.write( "t = (-b + or - square root(b^2 - 4ac)) / 2a \n" ); document.write( "we get the following solutions for t \n" ); document.write( "t = 6.813586792 or t = −0.376086792 \n" ); document.write( "we want the positive value for t, therefore \n" ); document.write( "the rocket will hit the ground in 6.8 seconds \n" ); document.write( "here is the graph \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |