document.write( "Question 981891: Ok so the problem is A rocket is launched from atop a 41 foot cliff with an initial velocity of 103 feet per second. The height of the rocket t seconds after launch is given by the equation \"h=-16%5E2%2B103t%2B41\". Graph the equation to find out how long after the rocket is launched it will hit the ground. Round to the nearest tenth of a second.
\n" ); document.write( "I know this is a large problem but please help and ill be very grateful.
\n" ); document.write( "I remember my math teacher asking this but it was 2 years ago so I forgot how to do it.
\n" ); document.write( " Please explain also.
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Algebra.Com's Answer #602807 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
The equation is
\n" ); document.write( "h = -16t^2 +103t + 41
\n" ); document.write( "this is a parabola that opens downward
\n" ); document.write( "to find time t when the rocket hits the round solve the following for t
\n" ); document.write( "-16t^2 +103t + 41 = 0
\n" ); document.write( "use quadratic formula,
\n" ); document.write( "t = (-b + or - square root(b^2 - 4ac)) / 2a
\n" ); document.write( "we get the following solutions for t
\n" ); document.write( "t = 6.813586792 or t = −0.376086792
\n" ); document.write( "we want the positive value for t, therefore
\n" ); document.write( "the rocket will hit the ground in 6.8 seconds
\n" ); document.write( "here is the graph
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+10%2C+-600%2C+200%2C+-16x%5E2+%2B103x+%2B+41%29+\"
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