document.write( "Question 981812: The midpoints of the sides of a triangle are at (0,-3) , (-1/2,7/2) and (-7/2,1/2) Find the coordinates of the vertices. \n" ); document.write( "
Algebra.Com's Answer #602798 by mananth(16946)\"\" \"About 
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The midpoints of the sides of a triangle are at (0,-3) , (-1/2,7/2) and (-7/2,1/2) Find the coordinates of the vertices.\r
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\n" ); document.write( "\n" ); document.write( "By mid point formula (x1+x2)/2 = 0 ;x1+x2=0............(1)\r
\n" ); document.write( "\n" ); document.write( "(x2+x3)/2 = -1/2 ; x2+x3=-1............(2)\r
\n" ); document.write( "\n" ); document.write( "(x1+x3)/2 = -7/2 ; x1+x3= -7.............(3)\r
\n" ); document.write( "\n" ); document.write( "substitute x2 in (1)\r
\n" ); document.write( "\n" ); document.write( "x1+(-1-x3) = 0
\n" ); document.write( "x1-x3=1.....(3)
\n" ); document.write( "solve with\r
\n" ); document.write( "\n" ); document.write( "x1+x3=-7.......(4)\r
\n" ); document.write( "\n" ); document.write( "add (3) & (4)
\n" ); document.write( "2x1=-6
\n" ); document.write( "x1=-3\r
\n" ); document.write( "\n" ); document.write( "x1+x3=-7
\n" ); document.write( "-3+x3=-7
\n" ); document.write( "x3= -4\r
\n" ); document.write( "\n" ); document.write( "x1+x2=0
\n" ); document.write( "x2=3\r
\n" ); document.write( "\n" ); document.write( "(x1=-3,x2=3,x3=-4)\r
\n" ); document.write( "\n" ); document.write( "Similarly solve for y1,y2,y3 \n" ); document.write( "
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