document.write( "Question 981876: a rectangle has a perimeter of 130 feet. the length is 2 more feet than twice the width. find the length and width. \n" ); document.write( "
Algebra.Com's Answer #602797 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Make Width = 'x'
\n" ); document.write( "Length = 2 + 2x
\n" ); document.write( "Perimeter = 2 x Length + 2 x Width
\n" ); document.write( "130 = 2(2 + 2x) + 2(x)
\n" ); document.write( "130 = 4 + 4x + 2x
\n" ); document.write( "Rearrange
\n" ); document.write( "6x = 130 - 4
\n" ); document.write( "6x = 126 feet
\n" ); document.write( "x = 126/6
\n" ); document.write( "x = 21 feet.
\n" ); document.write( "Width = 21 feet
\n" ); document.write( "Length = 44 feet
\n" ); document.write( "Hope this helps :-)
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