document.write( "Question 981876: a rectangle has a perimeter of 130 feet. the length is 2 more feet than twice the width. find the length and width. \n" ); document.write( "
Algebra.Com's Answer #602797 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make Width = 'x' \n" ); document.write( "Length = 2 + 2x \n" ); document.write( "Perimeter = 2 x Length + 2 x Width \n" ); document.write( "130 = 2(2 + 2x) + 2(x) \n" ); document.write( "130 = 4 + 4x + 2x \n" ); document.write( "Rearrange \n" ); document.write( "6x = 130 - 4 \n" ); document.write( "6x = 126 feet \n" ); document.write( "x = 126/6 \n" ); document.write( "x = 21 feet. \n" ); document.write( "Width = 21 feet \n" ); document.write( "Length = 44 feet \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |