document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=981874>Question 981874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> IN 10 years time a father will be twice as old as his daughter. 10 years he was six times as old as his daughter. How old is each now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #602793 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=602793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let fathers age now be x<BR>\n" );
document.write( "daughters age now be y\r<BR>\n" );
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document.write( "10 years hence<BR>\n" );
document.write( "(x+10)= 2(y+10)<BR>\n" );
document.write( "x+10 = 2y+20<BR>\n" );
document.write( "x-2y=10\r<BR>\n" );
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document.write( "10 years ago<BR>\n" );
document.write( "(x-10)= 6(y-10)<BR>\n" );
document.write( "x-10 = 6y-60<BR>\n" );
document.write( "x-6y=-50\r<BR>\n" );
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document.write( "x-2y=10<BR>\n" );
document.write( "x-6y=-50\r<BR>\n" );
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document.write( "subtract the equations\r<BR>\n" );
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document.write( "4y=60<BR>\n" );
document.write( "y=15 daughter's age now\r<BR>\n" );
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document.write( "substitute y in x-2y=10\r<BR>\n" );
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document.write( "so x=40 present father's age<BR>\n" );
document.write( " </SPAN>\n" );
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