document.write( "Question 981797: If the surface area of a cone of radius 6m is 96 pi, find the volume of the cone \n" ); document.write( "

Algebra.Com's Answer #602792 by Cromlix(4381) $\"\"$ $\"About$

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Hi there,
\n" ); document.write( "Surface Area of a cone =
\n" ); document.write( "pi x r^2 + pi x r x l
\n" ); document.write( "Surface Area = pir(r + l)
\n" ); document.write( "96pi/pi6 = 6 + l
\n" ); document.write( "16 = 6 + l
\n" ); document.write( "l (Slant height) = 10m
\n" ); document.write( "Using Pythagoras and a
\n" ); document.write( "right angled triangle
\n" ); document.write( "Hypotenuse = 10m
\n" ); document.write( "Base = 6m
\n" ); document.write( "To find height.
\n" ); document.write( "Height = √ 10^2 - 6^2
\n" ); document.write( "Height = √64
\n" ); document.write( "Volume of cone =
\n" ); document.write( "1/3 x pi x r^2 x h
\n" ); document.write( "1/3 x pi x 6^2 x √64
\n" ); document.write( "Volume = 301.6 m^3
\n" ); document.write( "Hope this helps:-) \n" ); document.write( "

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