document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83788>Question 83788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please can you help me with the following problem.<BR>\n" );
document.write( "Use the geometric sequence of numbers 1, 2, 4, 8,…to find the following:<BR>\n" );
document.write( "a) What is r, the ratio between 2 consecutive terms? <BR>\n" );
document.write( "b) Using the formula for the nth term of a geometric sequence, what is the 24th term?<BR>\n" );
document.write( "c) Using the formula for the sum of a geometric series, what is the sum of the first 10 terms? <BR>\n" );
document.write( "Thank you for your help.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60279 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1, 2, 4, 8....<BR>\n" );
document.write( "r = a selection / the previous number<BR>\n" );
document.write( "r = 2/1 = 4/2 = 8/4<BR>\n" );
document.write( "r = 2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "(2)^(n - 1) where n = 24<BR>\n" );
document.write( "2^(23) = 8,388,608<BR>\n" );
document.write( "...<BR>\n" );
document.write( "a(1 - r^n)/(1 - r)<BR>\n" );
document.write( "(1 - 2^n)/(1 - 2)<BR>\n" );
document.write( "2^10 - 1<BR>\n" );
document.write( "1023 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );