document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=981772>Question 981772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the system below:   a) solve the system by the linear combination method.  Show all work carefully.  B) check your answer.     X-2y=3    x+y=2 (y+3).    Please having a bit of trouble on this one! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #602747 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=602747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X-2y=3 --> x = 2y+3<BR>\n" );
document.write( "x+y=2 (y+3) --> x+y = 2y+6 --> x = y+6<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "x = 2y+3<BR>\n" );
document.write( "x = y+6<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "2y + 3 = y + 6<BR>\n" );
document.write( "y + 3 = 6<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "x = 9\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );