document.write( "Question 981766: Which solution set satisfies the absolute value function:|x-3|- 5 ≤ 2?\r
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\n" ); document.write( "c.) x ≤ -4 or x ≥ 10
\n" ); document.write( "d.) 6 ≤ x ≤ 10
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Algebra.Com's Answer #602715 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Instead of doing your problem for you, I'll do one EXACTLY IN EVERY\r\n" );
document.write( "DETAIL like yours.  Then you can use it as a model to solve yours by.\r\n" );
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document.write( "|x-2| - 7 ≤ 3\r\n" );
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document.write( "Add 7 to both sides\r\n" );
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document.write( "|x-2| ≤ 10\r\n" );
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document.write( "±(x-2) ≤ 10\r\n" );
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document.write( "Make two inequalities by using +(x-4) in one and -(x-4) in the other\r\n" );
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document.write( "+(x-2) ≤ 10        -(x-2) ≤ 10\r\n" );
document.write( "   x-2 ≤ 10          -x+2 ≤ 10\r\n" );
document.write( "     x ≤ 12           -x ≤ 8 \r\n" );
document.write( "                       x ≥ -8    (reversing because we divided by a negative)\r\n" );
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document.write( "x ≤ 12 says we shade left of 12 and x ≥ -8 says we shade right\r\n" );
document.write( "of -8.   So we do both, darkening the endpoints because the inequalities\r\n" );
document.write( "are ≤ and ≥, rather than < and >. \r\n" );
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document.write( "--------●===========================================================●------\r\n" );
document.write( "-10 -9 -8 -7 -6 -5 -4 -3 -2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12 13 14\r\n" );
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document.write( "That says we put -8 on the left, then ≤ x to stand for all the shaded \r\n" );
document.write( "part of the number line and a ≤ 12 on the right \r\n" );
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document.write( "Answer:   -8 ≤ x ≤ 12\r\n" );
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document.write( "Now do yours EXACLY the same way.\r\n" );
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document.write( "Edwin

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