Algebra.Com's Answer #60270 by jim_thompson5910(35256)  You can put this solution on YOUR website!  \n" );
document.write( " Distribute \n" );
document.write( " Combine like terms \n" );
document.write( " Subtract 5.96 to both sides \n" );
document.write( " Subtract 6x from both sides \n" );
document.write( " Combine like terms \n" );
document.write( "So our answer is \n" );
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document.write( "1. \n" );
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document.write( " Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition | \n" );
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document.write( " Lets start with the given system of linear equations \n" );
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document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa). \n" );
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document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero. \n" );
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document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 2 and 5 to some equal number, we could try to get them to the LCM. \n" );
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document.write( " Since the LCM of 2 and 5 is 10, we need to multiply both sides of the top equation by 5 and multiply both sides of the bottom equation by -2 like this: \n" );
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document.write( " Multiply the top equation (both sides) by 5 \n" );
document.write( " Multiply the bottom equation (both sides) by -2 \n" );
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document.write( " So after multiplying we get this: \n" );
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document.write( " Notice how 10 and -10 add to zero (ie ) \n" );
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document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them \n" );
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document.write( " Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether. \n" );
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document.write( " So after adding and canceling out the x terms we're left with: \n" );
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document.write( " Divide both sides by to solve for y \n" );
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document.write( " Reduce \n" );
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document.write( " Now plug this answer into the top equation to solve for x \n" );
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document.write( " Plug in  \n" );
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document.write( " Multiply \n" );
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document.write( " Subtract from both sides \n" );
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document.write( " Combine the terms on the right side \n" );
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document.write( " Multiply both sides by . This will cancel out on the left side. \n" );
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document.write( " Multiply the terms on the right side \n" );
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document.write( " So our answer is \n" );
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document.write( " ,  \n" );
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document.write( " which also looks like \n" );
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document.write( " ( , ) \n" );
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document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver) \n" );
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document.write( " we get \n" );
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document.write( " graph of (red) (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle). \n" );
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document.write( " and we can see that the two equations intersect at ( , ). This verifies our answer. | \n" );
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document.write( "2. \n" );
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document.write( " Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition | \n" );
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document.write( " Lets start with the given system of linear equations \n" );
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document.write( "  \n" );
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document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa). \n" );
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document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero. \n" );
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document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 1 and -2 to some equal number, we could try to get them to the LCM. \n" );
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document.write( " Since the LCM of 1 and -2 is -2, we need to multiply both sides of the top equation by -2 and multiply both sides of the bottom equation by -1 like this: \n" );
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document.write( " Multiply the top equation (both sides) by -2 \n" );
document.write( " Multiply the bottom equation (both sides) by -1 \n" );
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document.write( " So after multiplying we get this: \n" );
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document.write( " Notice how -2 and 2 add to zero, -10 and 10 add to zero, -20 and 20 and to zero (ie ) , and ) \n" );
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document.write( " So we're left with \n" );
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document.write( " which means any x or y value will satisfy the system of equations. So there are an infinite number of solutions \n" );
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document.write( " So this system is dependent | \n" );
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