document.write( "Question 981552: 1) If alfa,beta are real and alfa square,-beta square are the roots of the equation a2x2+x+(1-a2)=0,a>1,then beta square=_________\r
\n" ); document.write( "\n" ); document.write( "2)If (1-p) is aroot of a qadratic equation x2+px+(1-p)=0,then its roots are______ \n" ); document.write( "

Algebra.Com's Answer #602643 by josgarithmetic(39620) $\"\"$ $\"About$

You can put this solution on YOUR website!
This response deals with your second question.
\n" ); document.write( "If 1-p is a root, then you must be asking what is the other root for $\"x%5E2%2Bpx%2B%281-p%29=0\"$ .\r
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\n" ); document.write( "\n" ); document.write( "More than one way to go, but,
\n" ); document.write( " $\"x=%28-p%2B-+sqrt%28p%5E2-4%2A%281-p%29%29%29%2F2\"$ , using general formula for solution to a quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( " $\"x=%28-p%2B-+sqrt%28p%5E2-4%2B4p%29%29%2F2\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x=%28-p%2B-+sqrt%28p%5E2%2B4p-4%29%29%2F2\"$ ----------these would be the roots!\r
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\n" ); document.write( "\n" ); document.write( "You were expecting that 1-p is one of the roots. Check if it really is a root.
\n" ); document.write( " $\"%281-p%29%5E2%2Bp%281-p%29%2B%281-p%29\"$
\n" ); document.write( " $\"1-2p%2Bp%5E2%2Bp-p%5E2%2B1-p\"$
\n" ); document.write( " $\"1%2B1-2p%2Bp-p%2Bp%5E2-p%5E2\"$
\n" ); document.write( " $\"2-2p=0\"$ ------Not true, because this depends on the value of p.\r
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\n" ); document.write( "\n" ); document.write( "Your question or description for your exercise 2 is faulty. \n" ); document.write( "

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