document.write( "Question 83763: A chemist needs 100 milliliters of a 63% solution but has only 55% and 95% solutions available. Find how many milliliters of each that should be mixed to get the desired solution. \n" ); document.write( "
Algebra.Com's Answer #60264 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A chemist needs 100 milliliters of a 63% solution but has only 55% and 95% solutions available. Find how many milliliters of each that should be mixed to get the desired solution. \n" ); document.write( "--------------- \n" ); document.write( "Let amount of 55% solution be \"x\" ml ; Amt of active ingredient = 0.55x ml\r \n" ); document.write( "\n" ); document.write( "--------------- \n" ); document.write( "Amount of 95% solution is \"100-x\" ml ; Amt of active ingre. = 0.95(100-x) \n" ); document.write( "= 95-0.95x ml \n" ); document.write( "--------------------- \n" ); document.write( "Amount of 63% solution is 100 ml ; Amt of active ingre. 0.63(100) = 63 ml \n" ); document.write( "--------------- \n" ); document.write( "EQUATION: \n" ); document.write( "active + active = active \n" ); document.write( "0.55x + 95-0.95x = 63 \n" ); document.write( "-0.40x = -32 \n" ); document.write( "x= 80 ml (amount of 55% solution needed) \n" ); document.write( "100-80 = 20 ml (amount of 95% solution needed) \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "San \n" ); document.write( " |