document.write( "Question 981657: Catherine deposited a total of $13,000 between two saving accounts bearing simple interest. One of the accounts has an interest rate of 2% while the other rate is 3%. If the total interest earned after one year is $320, find the amount deposited into each of the accounts. \n" ); document.write( "
Algebra.Com's Answer #602625 by macston(5194)\"\" \"About 
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\n" ); document.write( "W=amount at 2%; H=amount at 3%
\n" ); document.write( ".
\n" ); document.write( "W+H=$13000
\n" ); document.write( "W=$13000-H Use this to substitute for W below.
\n" ); document.write( ".
\n" ); document.write( "0.02W+0.03H=$320 Substitute for W from above.
\n" ); document.write( "0.02($13000-H)+0.03H=$320
\n" ); document.write( "$260-0.02H+0.03H=$320 Subtract $260 from each side.
\n" ); document.write( "0.01H-$60 Divide each side by 0.01.
\n" ); document.write( "H=$6000 ANSWER 1: $6000 was in the 3% account.
\n" ); document.write( ".
\n" ); document.write( "W=$13000-H=$13000-$6000=$7000 ANSWER 2: $7000 was in the 2% account.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.02W+0.03H=$320
\n" ); document.write( "0.02($7000)+0.03($6000)=$320
\n" ); document.write( "$140+$180=$320
\n" ); document.write( "$320=$320
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