document.write( "Question 981603: Let Z be a standard normal random variable. Calculate the following probabilities:
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document.write( "P ( Z <= -1.56)
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document.write( "P ( Z > -1.07)
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document.write( "P ( 0.88 < Z < 1.37)\r
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document.write( "I did the last one on a calculator and came up with 0.587. I'm not confident that I did it correctly. All the previous ones in the homework look like this:
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document.write( "P ( Z <= c) = 0.8340. How do I find the probability without the c? \n" );
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Algebra.Com's Answer #602573 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Let Z be a standard normal random variable. Calculate the following probabilities: \n" ); document.write( "P ( Z <= -1.56) = normalcdf(-100,-1.56) = 0.0594 \n" ); document.write( "------------------------- \n" ); document.write( "P ( Z > -1.07) = normalcdf(-1.07,100) = 0.1423 \n" ); document.write( "------------------------- \n" ); document.write( "P ( 0.88 < Z < 1.37) = normalcdf(0.88,1.37) = 0.1041 \n" ); document.write( "------------------------------- \n" ); document.write( "I did the last one on a calculator and came up with 0.587. I'm not confident that I did it correctly. All the previous ones in the homework look like this: \n" ); document.write( "P ( Z <= c) = 0.8340. How do I find the probability without the c? \n" ); document.write( "Find the z-value with a left tail of 0.8340 \n" ); document.write( "Ans: invNorm(0.8340) = 0.9701 \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " |