document.write( "Question 83780: How do I :
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Algebra.Com's Answer #60256 by jim_thompson5910(35256)\"\" \"About 
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Since the first 400 natural numbers is\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,5,6,7...399,400\r
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\n" ); document.write( "\n" ); document.write( "The sequence is \r
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\n" ); document.write( "\n" ); document.write( "\"a%5Bn%5D=n\" where n starts at 1 and increments by 1\r
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\n" ); document.write( "\n" ); document.write( "So to find the sum of the arithmetic sequence \"a%5Bn%5D=n\" from 1 to 400 we can use this formula:\r
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\n" ); document.write( "\n" ); document.write( "\"S=n%28a%5B1%5D%2Ba%5Bn%5D%29%2F2\" where S is the sum, n is the number of terms (in this case 400), \"a%5B1%5D\" is the first term (in this case 1), and \"a%5Bn%5D\" is the last term (in this case 400)\r
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\n" ); document.write( "\n" ); document.write( "\"S=400%281%2B400%29%2F2\" Plug in n=400, \"a%5B1%5D=1\" and \"a%5Bn%5D=400\"\r
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\n" ); document.write( "\n" ); document.write( "\"S=400%28401%29%2F2\" Add\r
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\n" ); document.write( "\n" ); document.write( "\"S=160400%2F2\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"S=80200\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the sum of the first 400 natural numbers is 80,200
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