document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=981551>Question 981551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> triangle ABC has the vertices at A(4, 2), B(-3, 6), and C(1, -3). Find the length of the median of the triangle drawn to the side BC. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #602531 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=602531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "The median from BC to A<BR>\n" );
document.write( "Midpoint of BC<BR>\n" );
document.write( "(x1 + x2/2), (y1 = y2/2)<BR>\n" );
document.write( "Using (-3, 6) (1, -3)<BR>\n" );
document.write( "(-3 + 1/2 , (6 + (-3)/2)<BR>\n" );
document.write( "(-2/2) , (3/2) <BR>\n" );
document.write( "(-1, 3/2) Midpt<BR>\n" );
document.write( "Distance from Midpt to A<BR>\n" );
document.write( "Distance formula:<BR>\n" );
document.write( "sqrt (x2 - x1)^2 + (y2 - y1)^2<BR>\n" );
document.write( "Using (-1, 3/2) (4, 2)<BR>\n" );
document.write( "sqrt (4-(-1))^2 + (2 - (3/2))^2<BR>\n" );
document.write( "sqrt(5)^2 + (1/2)^2<BR>\n" );
document.write( "sqrt 25 + 1/4<BR>\n" );
document.write( "sqrt 101/4<BR>\n" );
document.write( "= 25.3 units<BR>\n" );
document.write( "Hope this helps:-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );