document.write( "Question 981453: If(~P->Q)->(PvR)is false, what are the truth values of P,Q and R? \n" ); document.write( "
Algebra.Com's Answer #602452 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! (~P->Q)->(PvR)is false\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So (~P->Q) is true while (PvR) is false. The generic form X->Y is only false if X is true but Y is false.\r \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "Since (PvR) is false this means that both P and R have to be false. Otherwise, (PvR) would be true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P is false, so ~P is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "~P is true and (~P->Q) is true. So Q has to be true. If Q were false, then (~P->Q) would be false.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=======================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = false \n" ); document.write( "Q = true \n" ); document.write( "R = false \n" ); document.write( " |