document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=981440>Question 981440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist has two solution of sulfuri acid a 20% solution and an 80% solution. how much of each should be used ro obtain 100 liters of a 62% solution? </SPAN>\n" );
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document.write( "Let x=liters of 20% solution<BR>\n" );
document.write( "0.20(x)+0.80(100L-x)=.62(100L)<BR>\n" );
document.write( "0.20x+80L-0.80x=62L<BR>\n" );
document.write( "-0.60x+80L=62L Add 0.60 x to each side.<BR>\n" );
document.write( "80L=0.60x+62L Subtract 62L from each side.<BR>\n" );
document.write( "18L=0.60x Divide each side by 0.60<BR>\n" );
document.write( "30L=x<BR>\n" );
document.write( "ANSWER 1: He should use 30 liters of 20% solution.<BR>\n" );
document.write( "100L-30L=70L<BR>\n" );
document.write( "ANSWER 2: He should use 70 liters of 80% solution.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( ".<BR>\n" );
document.write( "0.20(30)+0.80(70)=0.62(100)<BR>\n" );
document.write( "6L+56L=62L<BR>\n" );
document.write( "62L=62L </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );