document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=981433>Question 981433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice a certain whole number subtracted from 3 times the square of the number leaves 133. Find the number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #602437 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=602437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Twice a certain whole number subtracted <BR>\n" );
document.write( "from 3 times the square of the number <BR>\n" );
document.write( "leaves 133. <BR>\n" );
document.write( "3x^2 - 2x = 133<BR>\n" );
document.write( "3x^2 - 2x - 133 = 0<BR>\n" );
document.write( "Factorise<BR>\n" );
document.write( "(3x + 19)(x - 7)= 0<BR>\n" );
document.write( "3x + 19 = 0<BR>\n" );
document.write( "3x = -19<BR>\n" );
document.write( "x = -19/3<BR>\n" );
document.write( "x - 7 = 0<BR>\n" );
document.write( "x = 7<BR>\n" );
document.write( "so x can either equal<BR>\n" );
document.write( "-19/3 or 7<BR>\n" );
document.write( "Hope this helps:-) </SPAN>\n" );
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