document.write( "Question 981409: The 10th term of A.P is -5 and the 34th term is -57. Find the 15th term
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #602395 by Timnewman(323)![]() ![]() You can put this solution on YOUR website! Hi, \n" ); document.write( "Recall that the nth term of an A.P is giving by;T(n)=a+(n-1)d \n" ); document.write( "where a=first term \n" ); document.write( " d=commom difference. \n" ); document.write( "Now, if 10th term is -5, \n" ); document.write( "Therfore, a+9d=-5----(1) \n" ); document.write( " also,if 34th term is -57, \n" ); document.write( "then, a+33d=-57-----(2) \n" ); document.write( "from equ (1), \n" ); document.write( " a=-5-9d----(3) \n" ); document.write( "substitute for a in equ (2) \n" ); document.write( "i.e, -5-9d+33d=-57 \n" ); document.write( " 24d=-57+5 \n" ); document.write( "24d=-52 \n" ); document.write( "dividing bothsides by 24, \n" ); document.write( "d=-13/6 \n" ); document.write( "put d in equ (1) \n" ); document.write( " a=-5-9d \n" ); document.write( "a=-5-9(-13/6) \n" ); document.write( "a=-5+39/2 \n" ); document.write( "a=29/2 \n" ); document.write( "15th term(T(15)) =a+14d \n" ); document.write( " but a=29/2 \n" ); document.write( " d=-13/6 \n" ); document.write( "15th term=(29/2)+14(-13/6) \n" ); document.write( " =-95/6 \n" ); document.write( "You can put in mixed frction. \n" ); document.write( " |