document.write( "Question 981398: suppose you have $12,000 to invest. if part is invested at 10% and the rest at 15%, how much should be invested at each rate to yield 12% on the total amount invested? \n" ); document.write( "
Algebra.Com's Answer #602387 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x=invested at 10% \n" ); document.write( "12000-x=invested at 15%\r \n" ); document.write( "\n" ); document.write( ".10x+ (.15)(12000-x)=1440 ;; 12% of the total amount is 12% of $12000.\r \n" ); document.write( "\n" ); document.write( ".10x + 1800-.15x=1440 \n" ); document.write( "-0.05x=-360 \n" ); document.write( "x=7200\r \n" ); document.write( "\n" ); document.write( "12000-x=4800\r \n" ); document.write( "\n" ); document.write( "$7200 at 10%=$720 \n" ); document.write( "$4800 at 15%=$720\r \n" ); document.write( "\n" ); document.write( "That is $12000 earning $1440, and that is 12% \n" ); document.write( " |