document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=981399>Question 981399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Complete the square on the following quadratic\r<BR>\n" );
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document.write( "x2+14x+9=0\r<BR>\n" );
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document.write( "what value is added to both sides of the equation.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #602385 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=602385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+14x+9=0<BR>\n" );
document.write( "x^2+14x=-9<BR>\n" );
document.write( "take half of the x term and square it, adding that number to both sides of the equation.\r<BR>\n" );
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document.write( "x^2+14x+49= -9+49<BR>\n" );
document.write( "(x+7)^2=40<BR>\n" );
document.write( "x+7= sqrt (40)=+/- 2 sqrt 10<BR>\n" );
document.write( "x= -7 +/- 2 sqrt (10) </SPAN>\n" );
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