document.write( "Question 981360: x+4÷x-2<2÷x+1 \n" ); document.write( "
Algebra.Com's Answer #602366 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! If you mean the way you wrote it, then\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "The two zeros and the undefined x value give three critical values which form the x-number line into four intervals: \n" ); document.write( "The critical values are 0, 1, 2. \n" ); document.write( "The intervals on the x-axis are (-infinity,0), (0,1), (1,2), (2, infinity).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Test any value in each of the intervals and find if it satisfies or not, the inequality.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Trying x=-1, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "TRUE for (-infinity,0).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Try \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "FALSE for (0,1).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Try \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "TRUE for (1,2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Try 4, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "FALSE for (2, infinity)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is not yet completely solved. The value for x at 0 cannot be used or included, but the roots of the numerator in the single expression mean that x at 1 and x at 2 SHOULD still be checked, just to be sure of any more thorough solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You could try that... \n" ); document.write( " |