document.write( "Question 981360: x+4÷x-2<2÷x+1 \n" ); document.write( "
Algebra.Com's Answer #602366 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
If you mean the way you wrote it, then\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B4%2Fx-2%3C2%2Fx%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B4%2Fx-2-2%2Fx-1%3C0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B4-2x-2-x%29%2Fx%3C0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-3x%2B2%29%2Fx%3C0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28x-1%29%28x-2%29%29%2Fx%3C0\"
\n" ); document.write( "The two zeros and the undefined x value give three critical values which form the x-number line into four intervals:
\n" ); document.write( "The critical values are 0, 1, 2.
\n" ); document.write( "The intervals on the x-axis are (-infinity,0), (0,1), (1,2), (2, infinity).\r
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\n" ); document.write( "\n" ); document.write( "Test any value in each of the intervals and find if it satisfies or not, the inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B4%2Fx-2%3C2%2Fx%2B1\"
\n" ); document.write( "Trying x=-1,
\n" ); document.write( "\"-1%2B4%2F%28-1%29-2%3C2%2F%28-1%29%2B1\"
\n" ); document.write( "\"-1-4-2%3C-2%2B1\"
\n" ); document.write( "\"-7%3C-1\"
\n" ); document.write( "TRUE for (-infinity,0).\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B4%2Fx-2%3C2%2Fx%2B1\"
\n" ); document.write( "Try \"1%2F2\",
\n" ); document.write( "\"1%2F2%2B8-2%3C4%2B1\"
\n" ); document.write( "\"6%261%2F2%3C5\"
\n" ); document.write( "FALSE for (0,1).\r
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\n" ); document.write( "\n" ); document.write( "Try \"3%2F2\",
\n" ); document.write( "\"x%2B4%2Fx-2%3C2%2Fx%2B1\"
\n" ); document.write( "\"3%2F2%2B2%2A4%2F3-2%3C3%2B1\"
\n" ); document.write( "\"3%2F2%2B8%2F3-2%3C4\"
\n" ); document.write( "\"-1%2F2%2B8%2F3%3C4\"
\n" ); document.write( "\"2%262%2F3-1%2F2%3C4\"
\n" ); document.write( "TRUE for (1,2).\r
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\n" ); document.write( "\n" ); document.write( "Try 4,
\n" ); document.write( "\"x%2B4%2Fx-2%3C2%2Fx%2B1\"
\n" ); document.write( "\"4%2B1-2%3C1%2F2%2B1\"
\n" ); document.write( "\"3%3C3%2F2\"
\n" ); document.write( "FALSE for (2, infinity)\r
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\n" ); document.write( "\n" ); document.write( "This is not yet completely solved. The value for x at 0 cannot be used or included, but the roots of the numerator in the single expression mean that x at 1 and x at 2 SHOULD still be checked, just to be sure of any more thorough solution.\r
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\n" ); document.write( "\n" ); document.write( "You could try that...
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