document.write( "Question 83662: I am having trouble finding the answer to the equation and graphing it. In school we have not looked over this yet, (he gives us suprize questions) and i do not know how to answer it.
\n" ); document.write( "Y= X over 1 +1
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Algebra.Com's Answer #60236 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
I am not sure of how this problem was set-up. If it is:
\n" ); document.write( "Y= \"%28x%2F1%29%2B1%29\"
\n" ); document.write( "Than the answer is
\n" ); document.write( "y=x+1
\n" ); document.write( "To graph refer to the slope-intecept form of a line:
\n" ); document.write( "y=any y-term
\n" ); document.write( "m=the slope of the line
\n" ); document.write( "x=the corresponding x-term
\n" ); document.write( "b=the y-intercept (the point where the line crosses the y-axis at (0,b))
\n" ); document.write( ".
\n" ); document.write( "y=mx+b
\n" ); document.write( "y=x+1
\n" ); document.write( "The slope is 1 and the y-intercept is +1 or point (0, 1)
\n" ); document.write( "Graphing:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%2B1%29+\"
\n" ); document.write( ".
\n" ); document.write( "If the set-up is
\n" ); document.write( "y=\"%28x%2F%281%2B1%29%29\"
\n" ); document.write( "y=\"%28x%2F2%29\"
\n" ); document.write( "y=\"%28x%2F2%2B0%29\"
\n" ); document.write( "y=\"%281%2F2x%2B0%29\"
\n" ); document.write( "y=\"%28%281%2F2%29x%29\"
\n" ); document.write( "Than the slope is 1/2 and the y-intercept is 0 or the point (0, 0)
\n" ); document.write( "Graphing:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+%281%2F2%29x%29+\"
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