document.write( "Question 981343: Please help me solve this:
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document.write( "If z is a complex number such that the real part of (z+1)/(z-i) is 1, show that z lies on a straight line.\r
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document.write( "I tried to to multiply by the conjugate of the denominator and expanded and simplified and separated the the real and imaginary parts and got
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document.write( "{{x^2+y^2-y+x+i{x-y+1}}/{x^2+y^2-2y+1}
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document.write( "than I dropped the imaginary part i{x-y+1} and let the real part equal 1
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document.write( "{x^2+y^2-y+x}/{x^2+y^2-2y+1}=1
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document.write( "{x^2+y^2-y+x}=1{x^2+y^2-2y+1}
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document.write( "so I got y=1-x
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document.write( "Is that correct or have I missed anything?
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document.write( "Thank you very much, Jenny\r
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Algebra.Com's Answer #602344 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Doesn't get any better than that. Good job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it\r \n" ); document.write( "\n" ); document.write( " |