document.write( "Question 981345: A field is being built that has an area of 1000 square yards. The field must be 30 yards longer than its width. Determine algebraically the dimensions of the soccer field in yards \n" ); document.write( "
Algebra.Com's Answer #602343 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A=Area=1000yd^2; L=length; W=width=L-30yds \n" ); document.write( ". \n" ); document.write( "A=LW \n" ); document.write( "1000yds^2=(L)(L-30yds) \n" ); document.write( "1000yds^2=L^2-30L \n" ); document.write( "0=L^2-30L-1000 \n" ); document.write( "0=(L-50)(L+20) \n" ); document.write( "L-50=0 OR L+20=0 \n" ); document.write( "L=50 yards OR L=-20 yards \n" ); document.write( "ANSWER 1: The length of the field is 50 yards. \n" ); document.write( "W=L-30yds=50yds-30yds=20yds ANSWER 2: The width of the field is 20 yards. \n" ); document.write( ". \n" ); document.write( "The field is 50 yards by 20 yards. \n" ); document.write( " |