document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=981328>Question 981328</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify the expression (1-sec theta)(1+sec theta) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #602320 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=602320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Foiling them out, one gets f(x)=1-sec^2x\r<BR>\n" );
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document.write( "1-(1/cos^2x)=putting it over a common denominator<BR>\n" );
document.write( "[cos^2x-1]/cos^2x;  sin^2 x=(1-cos^2x);; sin^2x+cos^2x=1<BR>\n" );
document.write( "Therefore, this is - (sin^2 x)(/cos^2 x)= - tan^2 x\r<BR>\n" );
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document.write( "Identity is tan^2x+1=sec^2 x<BR>\n" );
document.write( "tan^2x=sec^2x-1<BR>\n" );
document.write( "-tan^2x=1-sec^2x\r<BR>\n" );
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