document.write( "Question 981319: x-y^2+6=0
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document.write( "2x^2+y^2-7-0
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document.write( "what are all possible (x,y) solutions? \n" );
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Algebra.Com's Answer #602316 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x-y^2+6=0 \n" ); document.write( "2x^2+y^2-7=0, editing\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=y^2-6;x^2=y^4-12y^2+36 \n" ); document.write( "substitute \n" ); document.write( "2y^4-24y^2+72+y^2-7=0\r \n" ); document.write( "\n" ); document.write( "2y^4-23y^2+65=0 \n" ); document.write( "(2y^2-13)(y^2-5)=0 \n" ); document.write( "2y^2=13 \n" ); document.write( "y^2=(13/2) \n" ); document.write( "y= +/- sqrt (26)/2; after rationalizing the denominator\r \n" ); document.write( "\n" ); document.write( "y^2=5 \n" ); document.write( "y= +/- sqrt (5)\r \n" ); document.write( "\n" ); document.write( "first equation becomes \n" ); document.write( "x-5+6=0; x+1=0, x=-1\r \n" ); document.write( "\n" ); document.write( "x=-1; y=+/- sqrt (5); +/- sqrt (26)/2\r \n" ); document.write( "\n" ); document.write( "second equation becomes \n" ); document.write( "2+5-7=0 ; checks \n" ); document.write( " |