document.write( "Question 981295: Exponential/Logarithmic Equations. Follow the directions of this equation.\r
\n" ); document.write( "\n" ); document.write( "Solve log(x plus 8) = 1 plus log(x minus 10)
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Algebra.Com's Answer #602293 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"log%28%28x+%2B8%29%29+=+1%2B+log%28%28x+-10%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x+%2B8%29%29-log%28%28x+-10%29%29+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x+%2B8%29%2F%28x+-10%29%29+=+1+\".....since \"1\" is \"log%2810%2C10%29\", we have\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x+%2B8%29%2F%28x+-10%29%29+=+log%28%2810%29%29+\"...if log same, then\r
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\n" ); document.write( "\n" ); document.write( "\"%28x+%2B8%29%2F%28x+-10%29+=+10+\"....solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+%2B8%29+=+10%28x+-10%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B8+=+10x+-100+\"\r
\n" ); document.write( "\n" ); document.write( "\"100+%2B8+=+10x+-x+\"\r
\n" ); document.write( "\n" ); document.write( "\"108+=+9x+\"\r
\n" ); document.write( "\n" ); document.write( "\"108%2F9+=+x+\"\r
\n" ); document.write( "\n" ); document.write( "\"x=12++\"\r
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