document.write( "Question 981211: Two numbers are such that the ratio between them is 3:5. If each is increased by 10, the ratio b/w the new numbers so formed as 5:7. Find the original number? \n" ); document.write( "
Algebra.Com's Answer #602244 by MathTherapy(10552)\"\" \"About 
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Two numbers are such that the ratio between them is 3:5. If each is increased by 10, the ratio b/w the new numbers so formed as 5:7. Find the original number?
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Let multiplicative factor be x
\n" ); document.write( "Then numbers are: 3x and 5x
\n" ); document.write( "We then get: \"%283x+%2B+10%29%2F%285x+%2B+10%29+=+5%2F7\"
\n" ); document.write( "7(3x + 10) = 5(5x + 10) -------- Cross-multiplying
\n" ); document.write( "21x + 70 = 25x + 50
\n" ); document.write( "21x - 25x = 50 - 70
\n" ); document.write( "- 4x = - 20
\n" ); document.write( "\"x+=+%28-+20%29%2F%28-+4%29\", or 5
\n" ); document.write( "Smaller original number: 3(5), or \"highlight_green%2815%29\"
\n" ); document.write( "Larger original number: 5(5), or \"highlight_green%2825%29\" \n" ); document.write( "
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