document.write( "Question 981149: x-2y=2 and x^2+5x+3y=3 \n" ); document.write( "
Algebra.Com's Answer #602234 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
What did you want with these? Solution for the two as a system? If that, you can solve first equation for x in terms of y, and then substitute this for x in the second (quadratic) equation. \r
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\n" ); document.write( "\n" ); document.write( "\"%282y%2B2%29%5E2%2B5%282y%2B2%29%2B3y=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"4y%5E2%2B8y%2B4%2B10y%2B10%2B3y=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"4y%5E2%2B21y%2B14=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"4y%5E2%2B21y%2B11=0\"
\n" ); document.write( "This is not easily factored.
\n" ); document.write( "\"y=%28-21%2B-+sqrt%28567%29%29%2F8\"-------after steps from formula of general solution to quadratic equation
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\n" ); document.write( "\"y=%28-21%2B-+9sqrt%287%29%29%2F8\"-----------and you can find the x values corresponding to each of these.
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