document.write( "Question 981192: need help using rules of implication and first five rules of replacment\r
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document.write( "N>~F
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document.write( "~(XvV)
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document.write( "(~VvJ)>(C&F)
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document.write( "/~N \n" );
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Algebra.Com's Answer #602218 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " 1. N>~F\r\n" ); document.write( " 2. ~(XvV)\r\n" ); document.write( " 3. (~VvJ)>(C&F)\r\n" ); document.write( " /~N\r\n" ); document.write( "\r\n" ); document.write( " 4. ~X&~V 2, DeMorgan\r\n" ); document.write( " 5. ~V&~X 4, Commutation\r\n" ); document.write( " 6. ~V 5, Simplification\r\n" ); document.write( " 7. ~(~VvJ)v(C&F) 3, Material Implication\r\n" ); document.write( " 8. (~~V&~J)v(C&F) 7, DeMorgan\r\n" ); document.write( " 9. (V&~J)v(C&F) 8, Double negation\r\n" ); document.write( "10. [Vv(C&F)]&[~Jv(C&F)] 9, Distribution\r\n" ); document.write( "11. [~~Vv(C&F)]&[~Jv(C&F)] 10, Double negation\r\n" ); document.write( "12. [~V>(C&F)]&[~Jv(C&F)] 11, Material Implication \r\n" ); document.write( "13. ~V>(C&F) 12, Simplification\r\n" ); document.write( "14. C&F 13,6, Modus ponens\r\n" ); document.write( "15. F 14, simplification\r\n" ); document.write( "16. ~~F>~N 1, transposition\r\n" ); document.write( "17. F>~N 16, Double negation\r\n" ); document.write( "18. ~N 17,15, Modus ponens\r\n" ); document.write( "\r\n" ); document.write( "Edwn\n" ); document.write( " |