document.write( "Question 981156: Find two consecutive positive integers such that the square of the second integer added to 5 times the first is equal to 229.omarroberts0 \n" ); document.write( "
Algebra.Com's Answer #602195 by LinnW(1048)\"\" \"About 
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Let x equal the first number
\n" ); document.write( "x + 2 equals the second number
\n" ); document.write( "The square of the second is (x + 2)^2
\n" ); document.write( "5 times the first number is 5(x)
\n" ); document.write( "(x + 2)^2 + 5(x) = 229
\n" ); document.write( "x^2 + 4x + 4 + 5x = 229
\n" ); document.write( "x^2 + 9x + 4 = 229
\n" ); document.write( "add -4 to each side
\n" ); document.write( "x^2 + 9x = 225
\n" ); document.write( "add -225 to each side
\n" ); document.write( "x^2 + 9x - 225 = 0
\n" ); document.write( "It turns out that there is not an integer solution to the equation
\n" ); document.write( "so there is not a solution to the problem as stated.
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