document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=981150>Question 981150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the surface area of a cylinder with a diameter of 50 and a height of 14. Use 3.14 for &#960; </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #602187 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=602187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the surface area of a cylinder with a diameter of 50 and a height of 14.<BR>\n" );
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document.write( "r = d/2 = 25<BR>\n" );
document.write( "The SA of each end is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The lateral area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%2Ah ALIGN=MIDDLE  ALT=\"2pi%2Ar%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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