document.write( "Question 981152: Find the cube roots of 27(cos 279° + i sin 279°).\r
\n" );
document.write( "\n" );
document.write( "My Work so far:\r
\n" );
document.write( "\n" );
document.write( "(27*(cos 279 + isin279)^1/3= 27^1/3 * (cos 279 + i sin 279) ^ 1/3
\n" );
document.write( "27 ^ 1/3 = cube root 27 = 3
\n" );
document.write( "3*(cos 279 + i sin 279) ^1/3= 3(cos 279/3 + i sin 279/3)= 3(cos 93 + i sin 93) \r
\n" );
document.write( "\n" );
document.write( "Is my answer right? \n" );
document.write( "
Algebra.Com's Answer #602177 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find the cube roots of 27(cos 279° + i sin 279°).\r \n" ); document.write( "\n" ); document.write( "My Work so far:\r \n" ); document.write( "\n" ); document.write( "(27*(cos 279 + isin279)^1/3= 27^1/3 * (cos 279 + i sin 279) ^ 1/3 \n" ); document.write( "27 ^ 1/3 = cube root 27 = 3 \n" ); document.write( "3*(cos 279 + i sin 279) ^1/3= 3(cos 279/3 + i sin 279/3)= 3(cos 93 + i sin 93) \r \n" ); document.write( "\n" ); document.write( "Is my answer right? \n" ); document.write( "====================== \n" ); document.write( "Your answer is right, but it's only 1 of the cube roots. \n" ); document.write( "There are 2 more. \n" ); document.write( " |