document.write( "Question 981120: Please could someone help with this question. I can't get the last part.\r
\n" ); document.write( "\n" ); document.write( "Find real numbers a and b with a>0 such that:
\n" ); document.write( "(a+ib)^2 = 1-1.875i\r
\n" ); document.write( "\n" ); document.write( "So far I have got this far.\r
\n" ); document.write( "\n" ); document.write( "a^2-b^2 +2abi = 1-1.875i
\n" ); document.write( "Real: a^2-b^2=1 (1)
\n" ); document.write( "Imaginary: 2ab = -1.875 (2)
\n" ); document.write( "Divide imaginary part (2) becomes: a =-0.9375/b (3)
\n" ); document.write( "I got 0.9375 =15/16\r
\n" ); document.write( "\n" ); document.write( "Sub in (1) gives:\r
\n" ); document.write( "\n" ); document.write( "(15/16)^2-b^4=b^2
\n" ); document.write( "b^4+b^2-225/256=0
\n" ); document.write( "From here I can not seem to factorize. Also I tried to use the quadratic formula but that didn't seem to work either.\r
\n" ); document.write( "\n" ); document.write( "Thank you in advance.
\n" ); document.write( "The answer given in the textbook is: a=5/4 and b=-3/4\r
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Algebra.Com's Answer #602142 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"%28a%2Bbi%29%5E2=1-1.875i\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2B2abi%2Bb%5E2%2Ai%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2%2Ai%5E2%2B2abi\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2%28-1%29%2B2abi\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2-b%5E2%2B2abi=1-1.875i\"\r
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\n" ); document.write( "\n" ); document.write( "Corresponding positions of the terms
\n" ); document.write( "\"system%28a%5E2-b%5E2=1%2C2ab=-1.875%29\"\r
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\n" ); document.write( "\n" ); document.write( "Use the second equation and substitute for b in the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2-%281.875%29%5E2%2F%284a%5E2%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"4a%5E4-4a%5E2-%281.875%29%5E2=0\"
\n" ); document.write( "Things from this quadratic-form equation in \"a\" are not very neat.
\n" ); document.write( "Some simplification after using formula for the general solution for quadratic equation gives \"highlight_green%28a%5E2=%281%2B-+sqrt%281%2B1.875%5E2%29%29%2F2%29\", not yet a to first power, so not done yet..., but at least you are finding a real number for a.\r
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\n" ); document.write( "Further computing for a^2 finally showed (with handheld calculator help),
\n" ); document.write( "\"a%5E2=1.5625\"
\n" ); document.write( "and since you're interested in positive values, find
\n" ); document.write( "\"highlight%28highlight%28a=1.25%29%29\".
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