document.write( "Question 981060: The average of 5 numbers is 25.After one of the numbers is removes,the average of the remaining numbers is 31.what no. Has been removed? \n" ); document.write( "
Algebra.Com's Answer #602069 by josgarithmetic(39620)\"\" \"About 
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The five numbers are of unknown value. Say u is four of them.
\n" ); document.write( "One of them is v.\r
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\n" ); document.write( "\n" ); document.write( "\"%284u%2Bv%29%2F5=25\"\r
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\n" ); document.write( "\n" ); document.write( "The average of four of them when v is removed becomes 31.\r
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\n" ); document.write( "\n" ); document.write( "\"4u%2F4=31\"\r
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\n" ); document.write( "\n" ); document.write( "\"u=31\"\r
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\n" ); document.write( "\n" ); document.write( "-\r
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\n" ); document.write( "\n" ); document.write( "Now solve for v.
\n" ); document.write( "\"4u%2Bv=5%2A25\"
\n" ); document.write( "\"v=5%2A25-4u\"
\n" ); document.write( "\"v=125-4%2A31\"
\n" ); document.write( "\"v=125-124\"
\n" ); document.write( "\"highlight%28v=1%29\"----------the number which was removed.
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