document.write( "Question 980959: Mark deposited $9,000 into two saving accounts bearing simple interest. One of the accounts has an interest rate of 8% while the other rate is 7%. If the total interest earned after one year is $700, find the amount deposited into each of the accounts \n" ); document.write( "
Algebra.Com's Answer #602009 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "E=amount in 8% account; S=amount in 7% account \n" ); document.write( ". \n" ); document.write( "E+S=$9000 \n" ); document.write( "S=$9000-E Use this to substitute for S below. \n" ); document.write( ". \n" ); document.write( "0.08E+0.07S=$700 Sub for S. \n" ); document.write( "0.08E+0.07($9000-E)=$700 \n" ); document.write( "0.08E+$630-0.07E=$700 Subtract %630 from each side. \n" ); document.write( "0.01E=$70 Divide each side by 0.01. \n" ); document.write( "E=$7000 ANSWER 1: He put $7000 in the 8% account. \n" ); document.write( ". \n" ); document.write( "S=$9000-E=$9000-$7000=$2000 ANSWER 2: He put $2000 in the 7% account. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "0.08E+0.07S=$700 \n" ); document.write( "0.08($7000)+0.07($2000)=$700 \n" ); document.write( "$560+$140=$700 \n" ); document.write( "$700=$700\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |