document.write( "Question 980846: Given that 3^x=9^x+1 work out the value of x.\r
\n" ); document.write( "\n" ); document.write( "My wrong workings:
\n" ); document.write( "3x=9x+1
\n" ); document.write( "X+1squareroot 3x=9
\n" ); document.write( "X=9-x+1squareroot3x
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Algebra.Com's Answer #601924 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"9%5Ex-3%5Ex=-1\"
\n" ); document.write( "\"%283%5E2%29%5Ex-3%5Ex=-1\"
\n" ); document.write( "\"%283%5E%282x%29%29-3%5Ex=-1\"
\n" ); document.write( "\"%283%5Ex%29%5E2-3%5Ex=-1\"
\n" ); document.write( "\"%283%5Ex%29%5E2-3%5Ex%2B1=0\"\r
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\n" ); document.write( "\n" ); document.write( "Pick an arbitrary new variable.
\n" ); document.write( "Let \"p=3%5Ex\", and rewrite the equation as
\n" ); document.write( "\"p%5E2-p%2B1=0\"\r
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\n" ); document.write( "\n" ); document.write( "Now first solve this equation for p.\r
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\n" ); document.write( "\n" ); document.write( "\"p=%281%2B-+sqrt%281%5E2-4%2A1%2A1%29%29%2F2\" according to general solution of a quadratic equation.
\n" ); document.write( "\"p=%281%2B-+sqrt%28-3%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"p=%281%2B-+i%2Asqrt%283%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Next substitute for p.
\n" ); document.write( "\"3%5Ex=%281%2B-+i%2Asqrt%283%29%29%2F2\", a complex result, still unfinished.
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\n" ); document.write( "Unless I made a mistake in the process, this is not a beginner's exercise. Maybe another tutor can carry this to a solution for x.
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