document.write( "Question 980798: John has 5 more nickels than dimes. If John has 1.75 how many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #601871 by macston(5194)    You can put this solution on YOUR website! . \n" ); document.write( "D=dimes, N=nickels \n" ); document.write( ". \n" ); document.write( "N=D+5 Use this to substitute for N below. \n" ); document.write( ". \n" ); document.write( "$0.05N+$0.10D=$1.75 Sub for N from above. \n" ); document.write( "$0.05(D+5)+$0.10D=$1.75 \n" ); document.write( "$0.05D+$0.25+$0.10D=$1.75 Subtract $0.25 from each side. \n" ); document.write( "$0.15D=$1.50 Divide each side by $0.15. \n" ); document.write( "D=10 \n" ); document.write( "ANSWER 1: He had 10 dimes. \n" ); document.write( ". \n" ); document.write( "N=D+5=10+5=15 \n" ); document.write( "ANSWER 2: He had 15 nickels. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "$0.05N+$0.10D=$1.75 \n" ); document.write( "$0.05(15)+$0.10(10)=$1.75 \n" ); document.write( "$0.75+$1.00=$1.75 \n" ); document.write( "$1.75=$1.75 \n" ); document.write( " \n" ); document.write( "  |