document.write( "Question 980725: If cos^2 x + cos x = 1. so, sin^12 x + 3 sin^10 x + 3 sin^8 x + sin^6 x = ? \n" ); document.write( "
Algebra.Com's Answer #601855 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If cos^2 x + cos x = 1. so, sin^12 x + 3 sin^10 x + 3 sin^8 x + sin^6 x = ? \n" ); document.write( " ------------ \n" ); document.write( " Solve for cos(x) \n" ); document.write( " cos^2 x + cos x = 1 \n" ); document.write( " cos^2 x + cos x - 1 = 0 \n" ); document.write( " ----- \n" ); document.write( " Sub u for cos(x) \n" ); document.write( " u^2 + u - 1 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " -------------- \n" ); document.write( " cos(x) = -1/2 + sqrt(5)/2 \n" ); document.write( " --- \n" ); document.write( " Find sin^2(x) \n" ); document.write( " sin^2 + cos^2 = 1 \n" ); document.write( " sin^2(x) = 1 - (1/4 - sqrt(5)/2 + 5/4) = -1/2 - sqrt(5)/2 \n" ); document.write( " -------------- \n" ); document.write( " sin^12 x + 3 sin^10 x + 3 sin^8 x + sin^6 x = sin^6(x)*(sin^6 + 3sin^4 + 3sin^2 + 1) \n" ); document.write( " = sin^6(x)*(sin^2 + 1)^3 \n" ); document.write( "------------ \n" ); document.write( "sin^6 = (sin^2)^3 = (1 + sqrt(5))/2 \n" ); document.write( "============== \n" ); document.write( "(1/2)*(1 + sqrt(5))*(-1/2)*(1 - sqrt(5)) \n" ); document.write( "= -(1/4)*(1 - 5) \n" ); document.write( "= 1 \n" ); document.write( "====================== \n" ); document.write( "Do the same for the other root, cos(x) = -1/2 - sqrt(5)/2 \n" ); document.write( " |