document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980759>Question 980759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the A = Pe^rt formula\r<BR>\n" );
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document.write( "The population of a town is presently about 25,000 people, and is growing at a rate of 3% peryear. How long will it take for the population to reach 40,000 people? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601844 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the A = Pe^rt formula\r<BR>\n" );
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document.write( "The population of a town is presently about 25,000 people, and is growing at a rate of 3% peryear. How long will it take for the population to reach 40,000 people?<BR>\n" );
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document.write( "40000 = 25000*e^(0.03t)<BR>\n" );
document.write( "e^(0.03t) = 40000/25000 = 1.6<BR>\n" );
document.write( "0.03t = ln(1.6)<BR>\n" );
document.write( "t = ln(1.6)/0.03<BR>\n" );
document.write( "t =~ 15.667 years </SPAN>\n" );
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