document.write( "Question 980660: the length of a rectangle is 7 cm longer than its width. if the perimeter of the rectangle is 74 cm. find the length and the area of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #601780 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
w width, L length, p perimeter\r
\n" ); document.write( "\n" ); document.write( "p=74\r
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\n" ); document.write( "\n" ); document.write( "\"system%28L=w%2B7%2C2w%2B2L=p%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2w%2B2%28w%2B7%29=p\"
\n" ); document.write( "\"2w%2B2w%2B14=p\"
\n" ); document.write( "\"4w=p-14\"
\n" ); document.write( "\"w=p%2F4-14%2F4\"
\n" ); document.write( "\"w=p%2F4-7%2F2\"
\n" ); document.write( "or maybe easier to use as \"w=%28p-14%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=%28p%2F4-14%2F4%29%2B7\"
\n" ); document.write( "\"L=p%2F4-14%2F4%2B28%2F4\"
\n" ); document.write( "\"L=%28p%2B14%29%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "\"w=%2874-14%29%2F4=15\", width
\n" ); document.write( "-
\n" ); document.write( "\"L=%2874%2B14%29%2F4=88%2F4=22\", length\r
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\n" ); document.write( "\n" ); document.write( "Area, \"wL=330\"
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