document.write( "Question 980601: If $\"+x=+sqrt%28pq%29+\"$ and $\"+y+=+%281%2F2%29+%28p%2Bq%29\"$ . Prove $\"x%3Cy\"$ \n" ); document.write( "

Algebra.Com's Answer #601733 by Edwin McCravy(20060) $\"\"$ $\"About$

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document.write( "The other tutor is right, so for the statement to be true, we must\r\n" );
document.write( "change the conclusion from  to \r\n" );
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document.write( "But that's not all we have to change.\r\n" );
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document.write( "The statement is also not true if p=-1, q=-9\r\n" );
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document.write( "For in that case  \r\n" );
document.write( "and  and x>y\r\n" );
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document.write( "The statement is also not true if p=0, q=-2\r\n" );
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document.write( "For in that case  \r\n" );
document.write( "and  and x>y\r\n" );
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document.write( "Also by symmetry it is not true if p=-2, q=0\r\n" );
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document.write( "So we must change your statement to something that is always true:\r\n" );
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document.write( "If , , , , prove \r\n" );
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document.write( "So what we are to prove becomes\r\n" );
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document.write( "If  and . Prove \r\n" );
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document.write( "To prove  is the same as proving \r\n" );
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document.write( "Let  and \r\n" );
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document.write( "Then  and \r\n" );
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document.write( "Then what we are to prove becomes:\r\n" );
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document.write( "If  and . Prove \r\n" );
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document.write( "So we consider \r\n" );
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document.write( "With the inclusion in the premise than p and q are non-negative and\r\n" );
document.write( "in the conclusion that  we have proved the statement. \r\n" );
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document.write( "Edwin

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